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42.25=-16t^2+60t+2
We move all terms to the left:
42.25-(-16t^2+60t+2)=0
We get rid of parentheses
16t^2-60t-2+42.25=0
We add all the numbers together, and all the variables
16t^2-60t+40.25=0
a = 16; b = -60; c = +40.25;
Δ = b2-4ac
Δ = -602-4·16·40.25
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-32}{2*16}=\frac{28}{32} =7/8 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+32}{2*16}=\frac{92}{32} =2+7/8 $
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